2898 is how much percent of 12600?

1.	2898 is how much percent of 12600?
A.	19%
B.	21%
C.	23%
D.	27%
Answer» D. 27%

Discussion

No Comment Found

Related MCQs

A student multiplied a number by 3 instead of 5 . 5 3 What is the percentage error in the calculation?
If 18 % of a number exceed its 14 % by 45, then the number is
Population of a city is 148000 and out of which 78000 are males and 40 percent population is literate. If 55 percent males are literate, then what is the number of females who are literate?
A number is divided into two parts in such a way that 30% of first part is 25 more than the 20% of second part. 50% of second part is 33.5 more than the 60% of first part. What is the number?
In an election between two candidates, 75% of the voters cast their votes, out of which 02% of the votes were declared invalid. A candidate got 9261 votes which were 75% of the total valid vote. Find the total number of voters.
Mridula runs a small pet shop. Her expense distribution is given as:90% in procurement and 10% in paying rents and electricity. If she spends Rs. 15,000 on rent and electricity on a monthly basis, then how much does the spend every month in procurement?
If a man saves 20% of his monthly salary. If on account of increase in prices, he is to increase his monthly expense by 20%, he is only able to save Rs. 800 per month. His monthly salary is:
If 85% of a number is added to 75, then the result is the number itself. The number is:
A tank full of petrol in a motorcycle lasts for 30 days. If a rider starts using 20% more petrol every day, then for how many days will the tank full of petrol last?
In an examination, 75% students passed from school A. The number of students appeared from school B is 20% more than that of A and the total number of students who passed the examination is 40% more than the number of students passed from A. What is the percentage of students passed from both schools to those who appeared from B?

2898 is how much percent of 12600?

Discussion

No Comment Found

Related MCQs

Reply to Comment