\[2{{x}^{2}}-(p+1)x+(p-1)=0\]. If \[\alpha -\beta =\alpha \beta \], then what is the value of p [Orissa JEE 2005]

\[2{{x}^{2}}-(p+1)x+(p-1)=0\]. If \[\alpha -\beta =\alpha \beta \], th

1.	\[2{{x}^{2}}-(p+1)x+(p-1)=0\]. If \[\alpha -\beta =\alpha \beta \], then what is the value of p [Orissa JEE 2005]
A.	1
B.	2
C.	3
D.	-2
Answer» C. 3

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\[2{{x}^{2}}-(p+1)x+(p-1)=0\]. If \[\alpha -\beta =\alpha \beta \], then what is the value of p [Orissa JEE 2005]

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