1.

\[2{{\tan }^{-1}}(\cos x)={{\tan }^{-1}}(\text{cose}{{\text{c}}^{2}}x),\] then x = [UPSEAT 2002]

A. \[\frac{\pi }{2}\]
B. \[\pi \]
C. \[\frac{\pi }{6}\]
D. \[\frac{\pi }{3}\]
Answer» E.


Discussion

No Comment Found

Related MCQs