\[2\,\,\left| \,\begin{matrix} 1 & 1 & 1 \\ a & b & c \\ {{a}^{2}}-bc & {{b}^{2}}-ac & {{c}^{2}}-ab \\ \end{matrix}\, \right|=\] [EAMCET 1991; UPSEAT 1999]

\[2\,\,\left| \,\begin{matrix} 1 & 1 & 1 \\ a & b & c \\

1.	\[2\,\,\left\| \,\begin{matrix} 1 & 1 & 1 \\ a & b & c \\ {{a}^{2}}-bc & {{b}^{2}}-ac & {{c}^{2}}-ab \\ \end{matrix}\, \right\|=\] [EAMCET 1991; UPSEAT 1999]
A.	0
B.	1
C.	2
D.	\[3abc\]
Answer» B. 1

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\[2\,\,\left| \,\begin{matrix} 1 & 1 & 1 \\ a & b & c \\ {{a}^{2}}-bc & {{b}^{2}}-ac & {{c}^{2}}-ab \\ \end{matrix}\, \right|=\] [EAMCET 1991; UPSEAT 1999]

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