100 mL of 0.01 \[M\,KMn{{O}_{4}}\] oxidises 100 mL \[{{H}_{2}}{{O}_{2}}\] in acidic medium. Volume of the same\[KMn{{O}_{4}}\] required in alkaline medium to oxidise 100 mL of the same \[{{H}_{2}}{{O}_{2}}\] will be (\[MnO_{4}^{-}\] changes to \[M{{n}^{2+}}\] in acidic medium and to \[Mn{{O}_{2}}\] in alkaline medium)

• A. \[\frac{100}{3}mL\]                  
• B. \[\frac{500}{3}mL\]
• C. \[\frac{300}{5}mL\]                  
• D. None