\[{{(1+i)}^{10}}\], where \[{{i}^{2}}=-1,\] is equal to [AMU 2001]

1.	\[{{(1+i)}^{10}}\], where \[{{i}^{2}}=-1,\] is equal to [AMU 2001]
A.	32 i
B.	64 + i
C.	24 i - 32
D.	None of these
Answer» B. 64 + i

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\[{{(1+i)}^{10}}\], where \[{{i}^{2}}=-1,\] is equal to [AMU 2001]

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