1 gram equivalent of $${{H}_{2}}S{{O}_{4}}$$ is treated with 112 g of $$KOH$$ for complete neutralization. Which of the following statements is correct?

Question

TuteeHUB · Accepted Answer

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TuteeHUB · Answer

13.7 kcal of heat is evolved with the formation of 87 g of $${{K}_{2}}S{{O}_{4}}$$, leaving no KOH.

TuteeHUB · Answer

27.4 kcal of heat is evolved with the formation of 87 g of $${{K}_{2}}S{{O}_{4}}$$, leaving 4 gram equivalent of KOH.

TuteeHUB · Answer

15.7 kcal of heat is evolved with the formation of 1 gram equivalent of$${{K}_{2}}S{{O}_{4}}$$, leaving 56 g of KOH.

TuteeHUB · Answer

13.7 kcal of heat is evolved with the formation of 87g of $${{K}_{2}}S{{O}_{4}}$$, leaving 1 gram equivalent of KOH.

1.	1 gram equivalent of \[{{H}_{2}}S{{O}_{4}}\] is treated with 112 g of \[KOH\] for complete neutralization. Which of the following statements is correct?
A.	13.7 kcal of heat is evolved with the formation of 87 g of \[{{K}_{2}}S{{O}_{4}}\], leaving no KOH.
B.	27.4 kcal of heat is evolved with the formation of 87 g of \[{{K}_{2}}S{{O}_{4}}\], leaving 4 gram equivalent of KOH.
C.	15.7 kcal of heat is evolved with the formation of 1 gram equivalent of\[{{K}_{2}}S{{O}_{4}}\], leaving 56 g of KOH.
D.	13.7 kcal of heat is evolved with the formation of 87g of \[{{K}_{2}}S{{O}_{4}}\], leaving 1 gram equivalent of KOH.
Answer» E.

1 gram equivalent of \[{{H}_{2}}S{{O}_{4}}\] is treated with 112 g of \[KOH\] for complete neutralization. Which of the following statements is correct?

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