MCQOPTIONS
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| 1. |
1.5 μg of enzyme gives a vmax of 3 μmol product produced per minute. What is the turnover number for this enzyme? |
| A. | 100 sec-1 |
| B. | 200 sec-1 |
| C. | 1000 sec-1 |
| D. | 2000 sec-1 |
| Answer» D. 2000 sec-1 | |