Find theprobability that the sum of the numbers showing on two dice is 8, given thatat least one die does not show five.
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Here,
`A = `Event that at least on die does not show `5`.
`:. n(A) = 5*5 = 25`
Let `B = `Event that sum of the dice is `8`.
Now, `(AnnB) = {(4,4),(2,6),(6,2)}`
`=>n(AnnB) = 3`
`:.` Required probability , `P(B/A) = (n(AnnB) )/(n(A)) = 3/25.`