The sum of a number and its positive square root is \(\frac{6}{25}\). The number is :
(a) 5
(b) \(\frac15\)
(c) 25
(d) \(\frac{1}{25}\)
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
The sum of a number and its positive square root is \(\frac{6}{25}\). The number is :
(a) 5
(b) \(\frac15\)
(c) 25
(d) \(\frac{1}{25}\)
The sum of a number and its positive square root is \(\frac{6}{25}\). The number is :
(a) 5
(b) \(\frac15\)
(c) 25
(d) \(\frac{1}{25}\)
(d) \(\frac1{25}\)
Let the number be x.
Then x + \(\sqrt{x}= \frac{6}{25}\)
⇒ 25x + 25\(\sqrt{x} = 6\)
Let \(\sqrt{x}\) = y. Then, the equation becomes
25y2 + 25y – 6 = 0
⇒ 25y2 + 30y – 5y – 6 = 0
⇒ 5y(5y + 6) – 1(5y + 6) = 0
⇒ (5y + 6)(5y – 1) = 0 ⇒ y = \(-\frac65,\frac15\)
Rejecting the negative value , \(\sqrt{x}\) = \(\frac15\) ⇒ x = \(\frac1{25}.\)