Find the roots of the equation 16x – \(\frac{10}{x}\) = 27
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
Find the roots of the equation 16x – \(\frac{10}{x}\) = 27
Find the roots of the equation 16x – \(\frac{10}{x}\) = 27
Given,
16x – \(\frac{10}{x}\) = 27
On multiplying x on both the sides we have,
⇒ 16x2 – 10 = 27x
⇒ 16x2 – 27x – 10 = 0
⇒ 16x2 – 32x + 5x – 10 = 0
⇒ 16x(x – 2) +5(x – 2) = 0
⇒ (16x + 5) (x – 2) = 0
Now, either 16x + 5 = 0 ⇒ x = \(\frac{-5}{16}\)
Or, x – 2 = 0 ⇒ x = 2
Thus, the roots of the given quadratic equation are x =\(\frac{-5}{16}\) and x = 2 respectively.