What is the equivalent weight of `P` in the following reaction?
`P_(4)+NaOH rarr NaH_(2)PO_(2)+PH_(3)`
A. `(31)/(4)`
B. `(31)/(3)`
C. `(31)/(2)`
D. `31xx4//3`
`P_(4)+NaOH rarr NaH_(2)PO_(2)+PH_(3)`
A. `(31)/(4)`
B. `(31)/(3)`
C. `(31)/(2)`
D. `31xx4//3`
Correct Answer – D
`P_(4) rarr NaH_(2)PO_(2)`
`(P_(4))^(@) rarr 4P^(+)+4e^(-)`
`:. ` Eq. wt. (Reductant) `=(P_(4))/(4)`
`(P_(4))^(@)+12e rarr 4p^(3-)`
`:.` Eq.wt.(Oxidant)`=(P_(4))/(12)`
`:.` Eq. wt. `(P_(4))=(P_(4))/(12)+(P_(4))/(12)`
`=P_(4)xx(16)/(48)=(4xx31)/(3)=31xx(4)/(3)`