The solution in a beaker turns blue if
A. Cu electrode is placed in `ZnSO_(4)` solution
B. Cu electrode is placed in `AgNO_(3)` solution
C. Cu electrode is placed in `Al_(2)(SO_(4))_(3)` solution
D. Cu electrode is placed in `FeSO_(4)` solution
A. Cu electrode is placed in `ZnSO_(4)` solution
B. Cu electrode is placed in `AgNO_(3)` solution
C. Cu electrode is placed in `Al_(2)(SO_(4))_(3)` solution
D. Cu electrode is placed in `FeSO_(4)` solution
Correct Answer – B
Cu being more reactive than Ag due to lower electrode potential, displaces Ag from `AgNO_(3)` solution. It is dissolved in the solution in the form of `Cu^(2+)` ions.