A plank `P` is placed on a solid cylinder `S`, which rolls on a horizontal surface. The two are of equal mass. There is no slipping at any of the surfaces in contact. The ratio of kinetic energy of `P` to the kinetic energy of `S` is:

A. `1:1`
B. `2:1`
C. `8:3`
D. `11:8`

A. `1:1`
B. `2:1`
C. `8:3`
D. `11:8`
Correct Answer – C
`KE` of `P=1/2m(2v)^(2)=2mv^(2)`
`KE` of `S=1/2mv^(2)+1/2Iomega^(2)=3/4mv^(2)implies (KE “of” P)/(KE “of” S)=8/3`