The number of atoms in 0.1 mol of a triatomic gas is:
A. (a)`6.026xx10^(23)`
B. (b)`1.806xx10^(23)`
C. (c )`3.600xx10^(23)`
D. (d)`1.80xx10^(23)`
A. (a)`6.026xx10^(23)`
B. (b)`1.806xx10^(23)`
C. (c )`3.600xx10^(23)`
D. (d)`1.80xx10^(23)`
Correct Answer – b
Let gas be `X_(3)`
Then `X_(3) -= 3X`
1 mol of `X_(3)` has 3 moles of `X` atoms
0.1 mol of `X_(3)` has `0.3` moles of `X` atoms
That is `0.3xxN_(A)`
0.1 mole has atoms `=0.1xx6.02xx10^(23)xx3`
`=1.806xx10^(23)`