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John Ram Jayaraman
Asked: 2022-11-09T06:49:44+05:30 In:

In a resonance pipe the first and second resonance are obtained at depths 22.7 cm and 70.2 respectively. What will be the end correction?
A. `1 .05` cm
B. `115.5` cm
C. `92.5` cm
D. `113. 5` cm

In a resonance pipe the first and second resonance are obtained at depths 22.7 cm and 70.2 respectively. What will be the end correction?
A. `1 .05` cm
B. `115.5` cm
C. `92.5` cm
D. `113. 5` cm
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  1. Correct Answer – a
    For and correction `x, (l_(1)+x)/(l_(1)+ x ) = (3lambda //4)/(lambda//4) =3`
    `rArr x= (l_(2)-3l_(1))/2=(70.2-3xx 22.7)/2`
    ` = 1.05` cm

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Damini Mistry
Asked: 2022-11-05T22:50:32+05:30 In:

In a resonance pipe the first and second resonance are obtained at depths 22.7 cm and 70.2 respectively. What will be the end correction?
A. `1.05 cm`
B. `115.5 cm`
C. `92.5 cm`
D. `113.5 cm`

In a resonance pipe the first and second resonance are obtained at depths 22.7 cm and 70.2 respectively. What will be the end correction?
A. `1.05 cm`
B. `115.5 cm`
C. `92.5 cm`
D. `113.5 cm`
Parabola
Leave an answer

Leave an answer

Browse

1 Answer

  1. Correct Answer – A
    For end correction `x`, `(l_2+x)/(l_1+x)=(3lamda//4)/(lamda//4)=3`
    `x=(l_2-3l_1)/(2)=(70.2-3xx22.7)/(2)=1.05cm`

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