0.4 g of polybasic acid HnA (all the hydrogens are acidic) requries 0.5 g of NaOH for complete neutralisation. The number of replaceable hydrogen atoms and the molecular weight of A would be (Mw of `acid=96)`
A. `2,94`
B. `1,95`
C. `3,93`
D. `4,92`
A. `2,94`
B. `1,95`
C. `3,93`
D. `4,92`
Correct Answer – D
`mEq Acid=mEq base`
`implies(0.4)/((Mw)/(n))xx1000=(0.5)/((40)/(1))xx1000`
`impliesn=3 and H_(n)A-=96impliesA=96-3xx1=93`