A uniform circular ring of radius `R` is first rotated about its horizontal axis with an angular velocity `omega_0` and then carefully placed on a rough horizontal surface as shown. The coefficient of friction between the surface and the rings `mu`. Time after which its angular speed is reduced to `0.5 omega_0` is

A. `(omega_(0)muR)/(2g)`
B. `(omega_(0)g)/(2muR)`
C. `(2 omega_(0)R)/(mug)`
D. `(omega_(0)R)/(2mug)`

A. `(omega_(0)muR)/(2g)`
B. `(omega_(0)g)/(2muR)`
C. `(2 omega_(0)R)/(mug)`
D. `(omega_(0)R)/(2mug)`
Correct Answer – D
Taking the `tau` about `C.M.`
`mu mG R=MR^(2)alpha,mug=RalpharArralpha=(mug)/R`
`omega=omega_(0)-(mug)/Rt=(omega_(0))/2, :. T=(omega_(0)R)/(2mug)`