If `C_(6)H_(12)O_(6)(s)+9O_(2)(g)rarr6CO_(2)(g)+6H_(2)O(g) , Delta H=-680` Kcal The weight of `CO_(2)(g)` produced when 170 Kcal of heat is evolved in the combustion of glucose is :-
A. 265 gm
B. 66 gm
C. 11 gm
D. 64 gm
A. 265 gm
B. 66 gm
C. 11 gm
D. 64 gm
Correct Answer – B
`C_(6)H_(12)O_(6(s))+9O_(2(g))rarr 5CO_(2(g))+6H_(2)O_((g)) , Delta H=-680 KCal` .
680 Kcal heat is released when 6 mole `CO_(2)` is produced so,
170 KCal heat is released when `((6)/(680)xx170)` mole `CO_(2)` is produced.
`therefore` Mass of `CO_(2)` produced `=(6)/(680)xx170xx44 g`
`=66 g CO_(2)`