A spherical ball of lead 6 cm in radius is melted and recast into three spherical balls. The radii of two of ball are 3 cm and 4 cm. What is the radius of third sphere?
1. 5 cm
2. 5.5 cm
3. 6 cm
4. 6.6 cm
1. 5 cm
2. 5.5 cm
3. 6 cm
4. 6.6 cm
Correct Answer – Option 1 : 5 cm
Given :-
Spherical ball of radius 6 cm
Recast into three spherical ball having radius = 3 cm and 4 cm
Concept :-
Volume of sphere = (4/3)πR3
Volume of spherical ball = Summation of volume of small spherical balls
Calculation :-
Let radius of small spheres are r1 , r2 and r3
r1 = 3 cm and r2 = 4 cm
Volume of sphere ball = Volume of first sphere + Volume of second sphere + Volume of third sphere
⇒ (4/3) × π × 63 = (4/3) × π × 33 + (4/3) × π × 43 + (4/3) × π × (r)3
⇒ (4/3) × π × 216 = (4/3) × π [27 + 64 + r3]
⇒ 216 = 91 + r3
⇒ 216 – 91 = r3
⇒ r3 = 125
⇒ r = ∛125
⇒ r = 5
∴ Radius of third small sphere is 5 cm