If the numerator of a fraction is increased by 0% and the denominator is increased by 40%, then the resultant fraction is \(\frac{{16}}{{63}}\). The original fraction is:
1. \(\frac{{4}}{{9}}\)
2. \(\frac{{16}}{{45}}\)
3. \(\frac{{5}}{{9}}\)
4. \(\frac{{2}}{{11}}\)
1. \(\frac{{4}}{{9}}\)
2. \(\frac{{16}}{{45}}\)
3. \(\frac{{5}}{{9}}\)
4. \(\frac{{2}}{{11}}\)
Correct Answer – Option 2 : \(\frac{{16}}{{45}}\)
Given:
Numerator is increased by 0%
Denominator is increased by 40%
Calculation:
Let numerator be x and denominator be y
According to the question,
100x/140y = 16/63
⇒ 5x/7y = 16/63
⇒ 45x = 16y
∴ \(\frac{{\rm{x}}}{{\rm{y}}} = \frac{{16}}{{45}}\)