X² +100x-300000=0Solve for x
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X is equal to – 600 or 500
We see that it is a quadratic polynomial.so, splitting the middle term,x²+100x-300000\xa0x²+600x – 500x – 300000 =0x(x+600) -500(x+600) = 0(x-500)(x+600) = 0X = 500 or X = -600
x2 + 100x – 300000 = 0x2 + 600x – 500x – 300000 = 0x(x + 600) – 500 (x + 600) = 0(x + 600) (x – 500) = 0x = -600 and x = 500