Without using trigonometric tables,prove that tan48°tan23°tan42°tan67°=1
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Are, dekho… tan(90-thita) = cot thita…. so agar tan 48 hai use tan(90-42) likha…. or use, cot 42° samjhe….. ab cot 42 × tan 42 = 1/tan42×tan42=1….. samjhe
Puja ni smj aaya yar
tan 48° tan 23° tan 42° tan 67° = tan (90° – 42°) tan (90° – 67°) tan 42° tan 67° = cot 42° cot 67° tan 42° tan 67° = (cot 42° tan 42°) (cot 67° tan 67°) = 1×1 = 1……………proved
Tan48° Tan23° Tan(90-48) Tan(90-23).Tan48 Tan23 Cot48 Cot23. 1